Three Phase Power Calculator

Calculate real, apparent, and reactive power for delta and wye three-phase systems

Connection Type
Wye (Y)
Star Connection
Delta (Δ)
Triangle Connection

What do you want to calculate?

Input Parameters
Line-to-Line
Line-to-Neutral
Results
Real Power (P)
0.00 W
Apparent Power (S)
0.00 VA
Reactive Power (Q)
0.00 VAR
Line Current
0.00 A
Phase Current
0.00 A
Power Factor
0.85
Phase Angle
0° degrees
Efficiency
0% %
Power Triangle
Interactive power triangle showing the relationship between Real (P), Reactive (Q), and Apparent (S) power

Power Factor Analysis

Current PF: 0.85
Good power factor range

Load Classification

Load Type: Balanced Resistive
Characteristic: Linear Load
Stable three-phase load with good balance

System Efficiency

Overall Efficiency: 85%
Good efficiency range

Recommendations

  • System operating within normal parameters

Motor Power Analysis

Motor Specifications
Full Load Current: 0 A
Starting Current: 0 A
Torque: 0 lb-ft
Protection Requirements
Overload Protection: 0 A
Short Circuit Protection: 0 A
Disconnect Size: 0 A

Cable Sizing Calculator

Cable Requirements
Minimum Cable Size: 0 mm²
Current Carrying Capacity: 0 A
Actual Voltage Drop: 0%
Cable Specifications
Conductor Material: Copper
Insulation Type: XLPE
Number of Cores: 3 + Earth

Harmonic Analysis

Harmonic Power: 0 W
K-Factor: 1.0

Harmonic Effects

• Increased heating in conductors
• Transformer derating required
• Potential resonance issues
• Neutral current in wye systems

Mitigation Recommendations

• Install harmonic filters
• Use K-rated transformers
• Consider 12-pulse drives
• Increase conductor sizing
Three Phase Power Equations
Wye (Star) Connection Equations:
Real Power:
P = √3 × VL × IL × cos(φ) = 3 × Vph × Iph × cos(φ)
Apparent Power:
S = √3 × VL × IL = 3 × Vph × Iph
Reactive Power:
Q = √3 × VL × IL × sin(φ) = 3 × Vph × Iph × sin(φ)
Voltage Relations:
VL = √3 × Vph, IL = Iph
Power Triangle:
S² = P² + Q², Power Factor = P/S = cos(φ)
Efficiency:
η = (Output Power / Input Power) × 100%
Note: VL = Line-to-Line Voltage, Vph = Phase Voltage, IL = Line Current, Iph = Phase Current, φ = Phase Angle

Star, Delta, and Where the √3 Comes From

In a balanced three-phase system, total real power is

P = √3 × VLL × IL × cosφ

The √3 arises because the three phases are 120° apart. Adding two phase voltages that are 120° apart gives a resultant √3 times larger than either, so line-to-line voltage is √3 times line-to-neutral voltage. Writing the total of three phase powers in terms of line quantities leaves that factor behind.

Star and delta differ in which quantity is shared

Star (wye)Delta
Line voltage√3 × phase voltage= phase voltage
Line current= phase current√3 × phase current
Neutral availableYesNo

The total power formula is identical for both, which is the point: expressed in line quantities, the connection does not matter. In a 400 V system the line-to-neutral voltage is 400/√3 ≈ 230 V, which is why the same supply serves both three-phase machinery and single-phase outlets.

This relationship is also what makes star-delta starting work: in star, each winding receives only 1/√3 of the line voltage, so starting current and torque both fall to about a third.

Why three-phase is used at all

Instantaneous power in a balanced three-phase system is constant rather than pulsating, because the three phases peak in sequence. A single-phase supply delivers power that varies between zero and twice its average at twice the supply frequency, which produces vibration and torque pulsation in motors. Three-phase machines run smoothly, are self-starting, and need no starting capacitor.

Three-phase also carries a given power with roughly 42% less line current than single-phase at the same voltage, so conductors, switchgear and transformers are all smaller for the same duty.

Frequently Asked Questions

What is the three-phase power formula?

P = √3 × VLL × IL × cosφ for a balanced load, using line-to-line voltage and line current. The same formula applies to both star and delta connections.

Where does the √3 come from?

From the 120° phase separation. Adding two voltages 120° apart gives a resultant √3 times larger, so line-to-line voltage is √3 times line-to-neutral voltage.

What is the difference between star and delta?

In star, line voltage is √3 times phase voltage and line current equals phase current, with a neutral available. In delta, line voltage equals phase voltage and line current is √3 times phase current, with no neutral.

Why is 400 V three-phase also 230 V single-phase?

Because line-to-neutral voltage is the line-to-line value divided by √3: 400/√3 ≈ 230 V. The same supply therefore serves both three-phase machinery and single-phase loads.

Why is three-phase better than single-phase?

Instantaneous power is constant rather than pulsating, so motors run smoothly and are self-starting. It also carries the same power with about 42% less line current, allowing smaller conductors and switchgear.

How does star-delta starting reduce current?

In star, each winding sees only 1/√3 of the line voltage, so starting current falls to about a third. Starting torque falls by the same factor, since torque follows the square of voltage.

Vinay Singh, author of this page

Written and reviewed by

Lead Electronic Engineer (R&D) · Power Electronics Specialist · M.E. Power Electronics

Founder of Power4All. Works in power-electronics R&D and writes the converter guides, calculators and simulators on this site.

Last updated

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