RL Time Constant Calculator

Time constant τ = L/R, settling time, and the rising current of an inductor-resistor circuit at any moment.
Time Constant & Current
Time to Reach %

Time Constant & Current at Time t

τ = L/R  •  Ifinal = V/R  •  i(t) = Ifinal(1 − e−t/τ)
100mH, 10Ω, 12V
1H, 100Ω, 24V
10µH, 5Ω, 5V
V
Enter values and press Calculate.

Time to Reach a Percentage of Final Current

t = −τ × ln(1 − X/100)  where X = target %
63.2% (1τ)
99.3% (5τ)
90%
%
Enter values and press Calculate.

The RL Time Constant

When a voltage is applied to an inductor and resistor in series, the current can't jump instantly — the inductor opposes the change. It rises exponentially toward its final value V/R, and the time constant τ = L/R sets how fast. After one time constant the current reaches 63.2% of its final value, and after about it is essentially complete (99.3%).

QuantityFormula
Time constantτ = L / R
Final currentIfinal = V / R
Current at time ti(t) = Ifinal(1 − e−t/τ)
Time to reach X%t = −τ·ln(1 − X/100)

Milestones: 1τ = 63.2%, 2τ = 86.5%, 3τ = 95%, 4τ = 98.2%, 5τ = 99.3%.

Real-World Applications & Examples

Worked examples

1. Relay coil. 100 mH, 10 Ω: τ=L/R=0.1/10=10 ms; it fully energizes in about 5τ=50 ms.
2. Final current. With 12 V applied, Ifinal=12/10=1.2 A once settled.
3. Current at 5 ms. Half a time constant: i=1.2×(1−e^(−0.5))=1.2×0.393=0.47 A.
4. Big choke. 1 H, 100 Ω: τ=10 ms; a larger inductance with higher resistance can give the same time constant.
5. Fast converter inductor. 10 µH, 5 Ω: τ=2 µs — the current changes very quickly, suiting high-frequency switching.
6. Time to 90%. t=−τ·ln(0.1)=2.3τ — for a 10 ms τ that is 23 ms to reach 90% of final current.

Frequently Asked Questions

What is the RL time constant?

It is τ = L/R, the time for the current in an inductor-resistor circuit to reach about 63.2% of its final value when energizing (or fall to 36.8% when de-energizing).

Why does inductor current rise gradually?

An inductor opposes changes in current by generating a back-EMF, so the current builds up exponentially rather than jumping instantly to its final value.

What is the final current?

Once fully energized the inductor looks like a plain wire, so the current settles at I = V/R, limited only by the resistance.

How long until the current is "fully on"?

About 5 time constants (5τ), by which the current reaches 99.3% of its final value — close enough to be considered complete.

What are the percentages at each time constant?

1τ = 63.2%, 2τ = 86.5%, 3τ = 95.0%, 4τ = 98.2%, 5τ = 99.3% of the final current.

How do I find the time to reach a given current?

Use t = −τ·ln(1 − X/100), where X is the target percentage of final current. For 90% that is about 2.3τ.

How does a larger inductance affect the time constant?

A larger L increases τ (slower current rise); a larger R decreases τ (faster rise), since τ = L/R.

Is the RL time constant the same when switching off?

The exponential shape is the same, but when de-energizing the current decays as e^(−t/τ) — and if the circuit opens abruptly, a large voltage spike appears.

What is the difference between RL and RC time constants?

Both are exponential, but RC = R×C governs a capacitor charging voltage, while RL = L/R governs an inductor current. Note R multiplies in RC but divides in RL.

Why does an inductor cause a voltage spike when switched off?

The inductor tries to keep its current flowing; if the path opens quickly, the rapid change produces a large back-EMF (V = L·di/dt). A freewheeling diode absorbs it safely.

Does the applied voltage change the time constant?

No — τ depends only on L and R. Voltage only scales the final current (V/R), not how fast it gets there.

What resistance should I use if the inductor is ideal?

Use the total series resistance in the loop, including the inductor's own winding resistance and any external resistor, since that is what limits and shapes the current.

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