Power Factor Correction Capacitor Calculator

Size the correction capacitor (kVAR and Farads) to raise a lagging load's power factor to a target value.
Single-Phase
Three-Phase

Single-Phase Correction Capacitor

Qc = P×(tanφ1−tanφ2)  •  C = Qc / (2πfV2)
5kW, 0.7→0.95, 230V/50Hz
2kW, 0.6→0.9, 120V/60Hz
10kW, 0.8→0.98, 230V/50Hz
kW
V
Hz
Enter values and press Calculate.

Three-Phase Correction Capacitor

Qc = P×(tanφ1−tanφ2)  •  Cper phase = Qc / (3×2πfVph2)
75kW, 0.75→0.95, 400V delta
150kW, 0.8→0.98, 415V star
30kW, 0.65→0.9, 480V delta
kW
V
Hz
Enter values and press Calculate.

How Power Factor Correction Works

A lagging (inductive) load draws more reactive power than necessary, forcing the utility to supply a higher apparent power (kVA) than the real power (kW) actually used. Adding a capacitor bank in parallel with the load supplies local reactive power, reducing the reactive current drawn from the source and raising the measured power factor toward 1.0 — without changing the real power consumed by the load at all.

QuantityFormulaMeaning
Existing reactive powerQ1 = P×tan(acos(PF1))Reactive power before correction
Target reactive powerQ2 = P×tan(acos(PF2))Reactive power allowed after correction
Correction capacitor sizeQc = Q1−Q2 = P(tanφ1−tanφ2)Reactive power the capacitor must supply
Single-phase capacitanceC = Qc / (2πfV²)Capacitor value across the supply
Three-phase capacitance (per phase)C = Qc / (3×2πfVph²)Vph=VLL for delta, VLL/√3 for star

Correcting all the way to PF=1.0 is rarely done in practice — most utilities and standards target 0.9–0.98 to avoid the cost and risk (over-correction can create a leading PF and resonance/overvoltage issues) of a perfectly unity system.

Real-World Applications & Examples

Worked examples

1. Small workshop, 5kW at PF 0.7→0.95. φ1=45.6°, φ2=18.2°: Qc=5×(1.020−0.329)=3.46 kVAR, C≈208 µF at 230V/50Hz.
2. US 120V/60Hz load. 2kW at PF 0.6→0.9: Qc=2×(1.333−0.484)=1.70 kVAR, C≈313 µF.
3. Larger facility, 10kW at PF 0.8→0.98. Qc=10×(0.75−0.203)=5.47 kVAR, C≈329 µF at 230V/50Hz.
4. Three-phase plant, 75kW at PF 0.75→0.95, delta bank at 400V. Qc=75×(0.882−0.329)=41.5 kVAR total, or ≈13.8 kVAR per phase → C≈275 µF per phase.
5. 150kW three-phase, star bank at 415V. Using phase voltage 415/√3≈240V, Qc=150×(0.75−0.203)=82 kVAR total, ≈27.3 kVAR/phase → C≈1517 µF per phase.
6. Utility penalty avoidance. Many utilities require PF≥0.9; a facility running at PF=0.75 that installs enough correction capacitance to reach 0.9 typically eliminates the low-PF demand penalty entirely.

Frequently Asked Questions

How do I calculate the correction capacitor size?

Find the reactive power reduction needed, Qc=P×(tanφ1−tanφ2), where φ1 and φ2 are acos of the existing and target power factors, then convert Qc to capacitance using C=Qc/(2πfV²).

Why does the capacitor go in parallel, not series, with the load?

A parallel capacitor supplies reactive current locally, cancelling part of the lagging reactive current drawn from the source, while keeping the load voltage unchanged — a series capacitor would instead drop voltage and is used for line compensation, not local PF correction.

What target power factor should I correct to?

Most utilities require 0.9–0.95 minimum; many industrial standards target 0.95–0.98. Correcting to exactly 1.0 is usually unnecessary and risks over-correction (leading PF).

What happens if I over-correct (capacitor too large)?

The load becomes net capacitive (leading PF), which can cause overvoltage, resonance with other capacitive/inductive equipment, and is often penalized by utilities just like a low lagging PF.

Does correction capacitance change with load?

Yes — PF correction is calculated for a specific real power P; if the load varies significantly, automatic switched capacitor banks are used to add/remove capacitance stages as load changes.

Why is capacitance calculated differently for star and delta banks?

A delta-connected bank sees the full line-to-line voltage across each capacitor, while a star-connected bank sees only the phase voltage (VLL/√3); since Q=ωCV², the lower star voltage needs a larger capacitance for the same kVAR.

Does correcting power factor reduce my energy bill?

It does not reduce kWh (real energy) charges, but it can eliminate low-PF demand penalties and, by reducing current draw, may allow smaller conductors/transformers and reduce I²R losses in the facility wiring.

Can power factor correction damage equipment?

Incorrectly sized capacitor banks can cause resonance with system inductance (harmonics amplification) or overvoltage from over-correction; always size correction capacitors conservatively and consider harmonic-filter-rated capacitors in facilities with variable-frequency drives.

What is the formula for capacitance from kVAR directly?

C = Qc(in VAR) / (2πfV²), where V is the RMS voltage across the capacitor and f is the supply frequency; remember to convert kVAR to VAR (×1000) before using this formula.

Why use tan(φ) instead of directly subtracting power factors?

Because reactive power is proportional to P×tanφ, not directly to PF; subtracting tanφ values (not PF values) gives the exact reactive power difference needed.

Is this calculator accurate for non-linear (harmonic) loads?

This calculator addresses displacement power factor (fundamental-frequency phase shift) only; loads with significant harmonics (VFDs, switch-mode supplies) need harmonic-rated capacitors and possibly detuning reactors — consult a power quality specialist for those cases.

How much can PF correction reduce line current?

Current is roughly proportional to kVA for a fixed voltage, so raising PF from 0.7 to 0.95 reduces apparent power (and thus current) by about 26% for the same real power delivered.

Do all three phases need equal capacitors in a balanced system?

Yes, for a balanced three-phase load, the correction capacitance should be split equally across all three phases (each sized per the per-phase Qc/3 as computed by the three-phase tab).

Should I round up to a standard capacitor bank size?

Yes — capacitor banks are sold in standard kVAR steps (e.g. 5, 10, 25, 50 kVAR); always select the nearest standard size at or slightly above the calculated Qc, never below it, to reliably reach your target PF.

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