Motor Starting Current Calculator

Inrush / locked-rotor current and starting torque for DOL, star-delta, autotransformer and soft starters.
Starting Current

Inrush Current & Starter Comparison

Istart(DOL) = FLA × LRC  •  Star-Delta ÷3  •  Autotransformer × tap²
13.6A, 6.5×, Star-Delta
30A, autotransformer 65%
50A, soft-starter 3×
A
× FLA
%
Enter values and press Calculate.

Why Motors Draw Huge Starting Current

At the instant of starting, an induction motor is like a short-circuited transformer — with the rotor stationary it draws a locked-rotor (inrush) current of typically 6–8 times the full-load current. This can cause voltage dips and nuisance tripping, so reduced-voltage starters are used on larger motors. Because both current and torque depend on the applied voltage, reducing the starting voltage cuts the inrush — but the starting torque falls with the square of the voltage, so there is always a trade-off.

StarterStarting currentStarting torque
Direct-on-line (DOL)FLA × LRC (100%)100%
Star-delta÷ 3 (33%)33%
Autotransformer (tap t)× t²× t²
Soft starter (limit I)set current limit∝ (I/IDOL

Star-delta starting connects the windings in star to start (each winding sees 1/√3 of line voltage), giving one-third of the DOL current and torque, then switches to delta to run. An autotransformer at tap t reduces the line starting current to t² of DOL. A soft starter ramps the voltage to hold the current to a chosen limit. Reduced-voltage methods suit loads that start unloaded (pumps, fans).

Real-World Applications & Examples

Worked examples

1. DOL start. FLA=13.6 A, LRC=6.5: Istart=13.6×6.5=88.4 A at 100% torque.
2. Star-delta. Same motor: Istart=88.4/3=29.5 A, but starting torque is only 33% of DOL.
3. Autotransformer 65% tap. 30 A FLA, LRC 7: DOL=210 A; line start=210×0.65²=210×0.4225=88.7 A, torque 42%.
4. Soft starter, 3× limit. 50 A FLA: Istart=3×50=150 A; torque ≈ (3/6)²=25% of DOL.
5. Torque trade-off. Star-delta cuts inrush to a third but also torque to a third — only suitable if the load starts light.
6. Voltage-dip check. If a supply can tolerate 90 A inrush, the 88.4 A DOL of example 1 is acceptable, but a larger motor would need a reduced-voltage starter.

Frequently Asked Questions

What is motor starting current?

It is the high current a motor draws at the instant of starting, when the rotor is stationary. Also called inrush or locked-rotor current, it is typically 6–8 times the full-load current for a direct-on-line start.

What is the locked-rotor multiple (LRC)?

It is the ratio of starting current to full-load current, usually 6–8 for standard induction motors. NEMA code letters (A–V) or the IEC starting-current ratio on the nameplate specify it.

How does star-delta starting reduce current?

Starting in star connects each winding to 1/√3 of the line voltage, which reduces both the starting current and the starting torque to one-third of the direct-on-line values. The motor then switches to delta to run.

How does an autotransformer starter work?

It applies a reduced voltage at a chosen tap (for example 65%) during starting. The line starting current falls to the square of the tap fraction (0.65² ≈ 0.42) of the DOL value, as does the starting torque.

Why does starting torque fall when I reduce current?

Motor torque is proportional to the square of the applied voltage, and current is proportional to voltage. So any voltage reduction that cuts current also cuts torque by the square — reducing inrush always costs starting torque.

What does a soft starter do?

A soft starter uses thyristors to ramp the voltage up smoothly, holding the current to a set limit (often 2–4 times FLA). This gives a controlled, gentle start with less mechanical and electrical stress than DOL.

When should I use direct-on-line starting?

DOL is simplest and cheapest and is fine for small motors or where the supply can handle the inrush and full starting torque is needed. Larger motors on weaker supplies usually need reduced-voltage starting.

How does starting current affect the supply?

The inrush causes a temporary voltage dip proportional to the current and the supply impedance. Too large a dip can dim lights, trip protection or stall other equipment, which is why inrush must be managed.

How long does the starting current last?

Only during acceleration, typically a fraction of a second to a few seconds depending on the load inertia. Once the motor reaches running speed, the current settles to the full-load value.

Does a VFD reduce starting current?

Yes, dramatically. A variable-frequency drive starts the motor at low frequency and voltage, so the starting current can be kept near the full-load value while still providing full torque — the gentlest starting method.

What is the difference between inrush and locked-rotor current?

They are often used interchangeably. Strictly, inrush is the very first transient peak (including a magnetising surge), while locked-rotor current is the sustained RMS current with the rotor held still; both are several times FLA.

How do I size protection for starting current?

Motor protection must allow the inrush to pass without tripping (using time-delayed or motor-rated breakers) while still protecting the cable. Short-circuit protection is set above the locked-rotor current but below the fault level.

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