Power Dissipation Calculator

Power a component dissipates — from V×I, from efficiency, or averaged under a duty-cycled pulse.
From V & I
From Efficiency
Duty-Cycled Pulse

Direct Dissipation (V × I)

P = V × I  •  P = I² × R  •  P = V² / R
Diode: 0.7V, 2A
Resistor: 3A, 10Ω
Regulator drop: 5V, 1A
V
A
Ω
Enter values and press Calculate.

Dissipation from Efficiency

Ploss = Pin × (1−η) = Pout × (1−η)/η
50W in, 90% eff
20W out, 85% eff
W
%
Enter values and press Calculate.

Average Power Under a Duty-Cycled Pulse

Pavg = D × Pon  (D = ton/T, as a fraction)
10W pulse, 25% duty
2W pulse, 50% duty
W
%
Enter values and press Calculate.

How to Find Power Dissipation

Every real component wastes some energy as heat, which is what actually determines its temperature rise and cooling needs. There are three common starting points for finding this loss. If you know the voltage and current at the device, dissipation is simply P = V×I (or the resistive forms I²R and V²/R). If you only know the system's efficiency, the loss is the fraction (1−η) of whichever power figure you have. And if the device is switched on and off repeatedly, its average heating depends on how much of the time it is actually on — the duty cycle.

MethodFormula
From V & IP = V × I
From R & IP = I² × R
From R & VP = V² / R
From input power & efficiencyPloss = Pin×(1−η)
From output power & efficiencyPloss = Pout×(1−η)/η
Duty-cycled averagePavg = D × Pon

This dissipated power P is exactly the input needed by the Junction Temperature and Heat Sink calculators — find P here, then feed it into those tools to size cooling.

Real-World Applications & Examples

Worked examples

1. Rectifier diode. Vf=0.7 V, If=2 A: P=0.7×2=1.4 W.
2. Load resistor. I=3 A through 10 Ω: P=I²R=3²×10=90 W.
3. Linear regulator. 5 V dropout at 1 A: P=5×1=5 W — all of it turned to heat.
4. From efficiency. 50 W input at 90% efficiency: Ploss=50×0.1=5 W.
5. From output & efficiency. 20 W output at 85%: Ploss=20×0.15/0.85=3.53 W.
6. PWM-dimmed LED driver. 10 W on-state loss at 25% duty: Pavg=0.25×10=2.5 W average heating, far less than running continuously.

Frequently Asked Questions

What is power dissipation?

It is the electrical power converted to heat in a component rather than doing useful work — the rate at which a device warms up. It is measured in watts and is the key input to thermal (cooling) design.

How do I calculate power dissipation from voltage and current?

Multiply them: P = V×I. This works for any two-terminal device where you know the voltage across it and the current through it, such as a diode, LED, or a switch's on-state drop.

How do I find dissipation in a resistor?

Use P = I²R if you know the current, or P = V²/R if you know the voltage across it. Both give the same answer as P=V×I for a purely resistive component.

How do I find power loss from efficiency?

If you know the input power, loss is Pin×(1−η). If you only know the output power, use Pout×(1−η)/η instead, since the input is Pout/η.

Why is efficiency-based loss useful?

Manufacturers often specify a converter's or regulator's efficiency rather than its internal loss breakdown, so this lets you quickly estimate the heat it generates without knowing every internal loss mechanism.

What is duty-cycled average power?

When a device is switched on and off repeatedly (e.g. PWM control), its average heating is less than its full on-state power, scaled by the fraction of time it is actually on: Pavg=D×Pon, where D is the duty cycle (0–1).

Is average power enough, or should I also check peak power?

Average power sets the long-term temperature rise, but peak (on-state) power still matters for instantaneous voltage/current ratings and short-term thermal transients, especially for slow-thermal-mass parts.

How does this relate to junction temperature?

The dissipated power P found here is exactly what you plug into a thermal-resistance formula, Tj = Ta + P×θ, to find how hot the device actually gets — see the Junction Temperature calculator.

Does power dissipation include switching loss?

The V×I and resistive formulas here capture steady-state (conduction) loss. Devices that switch on and off at high frequency also have switching loss, which is calculated separately — see the Switching Loss calculator.

What is a typical acceptable power dissipation?

It depends entirely on the package and cooling: a small SOT-23 transistor might handle under 0.5 W without a heatsink, while a TO-220 device with a heatsink can handle many watts. Always check the datasheet's maximum power rating.

Can I add multiple loss sources together?

Yes. Total dissipation is simply the sum of every loss mechanism present — conduction, switching, quiescent/bias current, etc. Compute each separately (using the appropriate tool) and add them for the total thermal design power.

Does ambient temperature affect power dissipation?

Not the dissipation itself (which depends on electrical conditions), but it strongly affects the resulting temperature rise and therefore how much dissipation is safe — see the Junction Temperature and Heat Sink calculators.

Related Calculators

Junction TemperatureSwitching LossHeat Sink CalculatorAll Calculators