Single-Phase Full-Wave Centre-Tapped Rectifier

A centre-tapped full-wave rectifier uses a centre-tapped transformer and just two diodes to convert both halves of the AC input into pulsating DC.

Introduction

A rectifier is a circuit that converts alternating current (AC) into direct current (DC). In an earlier tutorial we looked at the half-wave rectifier, which uses only one half of the AC cycle, and the bridge full-wave rectifier, which uses both halves with four diodes. In this tutorial we cover the second type of full-wave rectifier — the centre-tapped full-wave rectifier — and see exactly how it turns a full AC cycle into DC using only two diodes.

Because it processes both the positive and negative half-cycles, a full-wave rectifier delivers roughly double the average DC voltage of a half-wave rectifier, with lower ripple that appears at twice the supply frequency — making it much easier to smooth into clean DC. Full-wave rectifiers come in two forms:

  • Centre-Tapped Full-Wave Rectifier — two diodes with a centre-tapped transformer (this page)
  • Bridge Full-Wave Rectifier — four diodes, no centre tap needed

What is a Centre-Tapped Transformer?

This rectifier gets its name from the special transformer it needs. A normal transformer has a single continuous winding on the secondary side. A centre-tapped transformer adds one extra connection — a wire brought out from the exact middle of the secondary winding, called the centre tap (CT).

That centre tap splits the secondary into two equal halves. Each half produces the same voltage, but because they are measured from a common midpoint, the two voltages are equal in magnitude and opposite in polarity at any instant. If the peak voltage of one half (centre tap to one end) is Vm, then the full end-to-end secondary voltage peak is 2Vm. This dual, out-of-phase supply is exactly what lets us rectify both half-cycles with only two diodes.

Centre-tapped transformer construction showing the secondary winding split into two equal halves by a centre tap
Figure 2: A centre-tapped transformer splits the secondary into two equal, opposite voltages

Circuit Diagram & Construction

A single-phase full-wave centre-tapped rectifier is built from three main parts:

  • A centre-tapped transformer that supplies the two equal, opposite secondary voltages
  • Two diodes — labelled D1 and D2
  • A resistive load RL

The two ends of the secondary winding (A and B) connect to the anodes of D1 and D2. The two diode cathodes are joined together to form the positive output terminal, and the centre tap forms the common return (negative terminal). The load RL is connected between the joined cathodes and the centre tap, as shown below.

Single-phase full-wave centre-tapped rectifier circuit diagram with two diodes D1 and D2, centre-tapped transformer and load resistor RL
Figure 1: Centre-tapped full-wave rectifier circuit diagram

Notice the key difference from the bridge rectifier: a bridge circuit needs four diodes and an ordinary transformer, while the centre-tapped circuit needs only two diodes but a more complex centre-tapped transformer.

Working Principle

Because the two secondary halves are always opposite in polarity, one diode is forward-biased while the other is reverse-biased on every half-cycle. The trick is that whichever diode conducts, the current is steered through the load RL in the same direction — which is what produces a full-wave DC output.

Positive Half-Cycle — Diode D1 Conducts

During the positive half-cycle of the AC input, end A of the secondary is positive with respect to the centre tap, while end B is negative. This forward-biases D1, so it conducts, and reverse-biases D2, so it blocks. Current flows from A, through D1, down through the load RL, and back to the transformer through the centre-tap connection.

Positive half-cycle operation: diode D1 forward-biased and conducting, diode D2 reverse-biased, current flowing through the load
Figure 3: Positive half-cycle — D1 conducts, D2 blocks

Negative Half-Cycle — Diode D2 Conducts

When the input swings into its negative half-cycle, the secondary polarities reverse: end B becomes positive with respect to the centre tap and end A becomes negative. Now D2 is forward-biased and conducts, while D1 is reverse-biased and blocks. Current flows from B, through D2, and down through RLin the same direction as before — then back through the centre tap.

Negative half-cycle operation: diode D2 forward-biased and conducting, diode D1 reverse-biased, load current in the same direction as before
Figure 4: Negative half-cycle — D2 conducts, D1 blocks

Since D1 handles the positive half and D2 handles the negative half, the load receives current on both half-cycles, always in the same direction. The result is a full-wave rectified — but still pulsating — DC voltage that usually needs a filter capacitor before it can be used as a clean DC supply.

Output Waveform

The waveform below is drawn directly from the working principle above. It stacks three synchronized views on the same time axis (ωt): the two secondary voltages, which diode is conducting, and the resulting output across the load.

Centre-tapped full-wave rectifier waveforms: secondary voltages, diode conduction, and full-wave rectified output
Figure 5: Full-wave centre-tapped rectifier waveforms — secondary voltages, diode conduction, and rectified output

Parts of the Waveform Explained

  • Secondary voltages Va and Vb: the centre tap produces two sine voltages of equal peak Vm that are exactly 180° out of phase. When Va is positive, Vb is negative, and vice-versa.
  • Conduction bands (D₁ / D₂): a diode conducts only when its half of the winding is positive. So D1 conducts from 0 to π (positive half of Va) and D2 conducts from π to 2π (positive half of Vb) — then the pattern repeats.
  • Output voltage Vo: because whichever diode is on always steers current the same way through RL, the load sees a positive hump on every half-cycle. The result is a series of half-sine humps — full-wave rectified, pulsating DC.
  • Peak value Vm: each hump rises to the peak of one winding half (Vm, less one diode drop in a real circuit — see Peak Output Voltage).
  • Average value Vdc: the orange dashed line is the DC (average) level the load actually experiences, Vdc = 0.637 Vm — twice the average of a half-wave rectifier.
  • Ripple & frequency: the output dips to zero between humps rather than staying flat — this variation is the ripple. Since there are two humps per input cycle, the ripple frequency is 2f and the ripple period is T/2 — 100 Hz for a 50 Hz supply (120 Hz for 60 Hz). The higher ripple frequency is easier and cheaper to smooth with a filter capacitor.
  • Time axis (ωt): one full input cycle spans 0→2π (period T), but the output pattern repeats every π (period T/2) — which is exactly why the DC is "full-wave".

Key Parameters & Formulas

For an ideal centre-tapped full-wave rectifier feeding a resistive load, where Vm is the peak voltage of each half of the secondary (centre tap to one end):

QuantityFormula & Value
Average (DC) output voltageVdc = 2Vm/π ≈ 0.637 Vm
RMS output voltageVrms = Vm/√2 ≈ 0.707 Vm
Average load currentIdc = 2Im/π ≈ 0.637 Im
Ripple factorr = 0.482 (48.2%)
Rectification efficiencyηmax = 81.2%
Form factorFF = 1.11
Peak factorPF = √2 ≈ 1.414
Peak Inverse Voltage (each diode)PIV = 2Vm
Output ripple frequencyfripple = 2f (100 Hz for 50 Hz)
Transformer Utilization FactorTUF ≈ 0.672

Peak Output Voltage

An important practical detail: the load only ever "sees" half of the total secondary voltage at a time, because at any instant only one half of the winding (centre tap to one end) is driving the conducting diode. So the peak output is set by Vm, the peak of a single half — not the full end-to-end secondary voltage.

A real silicon diode also drops about 0.7 V when conducting. Because only one diode is ever in the current path, only one diode drop is subtracted from each half-cycle:

Vout(peak) = Vm − VF ≈ Vm − 0.7 V

Losing only one diode drop (versus two in a bridge rectifier) is the main efficiency advantage of the centre-tapped design — which is why it was historically preferred for low-voltage supplies where every volt matters.

Peak Inverse Voltage (PIV)

The peak inverse voltage is the maximum reverse voltage a diode must withstand while it is blocking. Consider the positive half-cycle, when D1 conducts and D2 is off. The reverse-biased diode D2 is connected across both halves of the secondary at once, so it must block the full end-to-end secondary voltage minus the small drop across the conducting diode:

PIV = 2Vm − VF ≈ 2Vm

This is the key trade-off of the centre-tapped rectifier: each diode must be rated for roughly twice the peak voltage compared with a bridge rectifier, whose diodes only need to withstand Vm. When selecting diodes, always choose a reverse-voltage rating comfortably above 2Vm.

Peak inverse voltage in a centre-tapped full-wave rectifier: the blocking diode withstands twice the peak half-winding voltage, PIV equals 2Vm
Figure 6: The blocking diode must withstand PIV = 2Vm

Centre-Tapped vs Bridge Rectifier

Both circuits give full-wave rectification, but they make different engineering trade-offs:

ParameterCentre-TappedBridge
Number of diodes24
TransformerCentre-tapped (special)Ordinary secondary
Diode drops in path1 (higher efficiency)2
PIV per diode2VmVm
Peak output voltageVm − 0.7 VVm − 1.4 V
Transformer utilizationLower (~0.672)Higher (~0.812)
Typical useLow-voltage suppliesGeneral-purpose supplies

Advantages & Disadvantages

Advantages

  • Only two diodes, with a single diode drop in the conduction path — better efficiency at low output voltages.
  • Full-wave output: higher average DC and lower ripple than a half-wave rectifier.
  • Ripple is at twice the supply frequency, so smaller/cheaper filtering is needed.
  • The centre tap gives a natural common ground between the input and output.

Disadvantages

  • Needs a centre-tapped transformer, which is larger, heavier and more expensive.
  • Each diode must withstand a high PIV = 2Vm.
  • Only half the secondary winding is used at any instant, giving a lower transformer utilization factor than the bridge rectifier.

Applications

  • Low-voltage linear DC power supplies where minimizing the diode drop matters.
  • Battery chargers and DC adaptors.
  • Audio amplifier and instrumentation supplies that need a centre-ground reference.
  • Classic vacuum-tube heater/HT supplies and educational laboratory rectifiers.

Frequently Asked Questions – FAQs

It is a full-wave rectifier that uses a centre-tapped transformer and two diodes. Each diode conducts on alternate half-cycles, converting both halves of the AC input to DC while steering current through the load in a single direction.

The centre tap provides a permanent return path. Each half of the secondary winding, combined with one diode, forms a complete rectifying circuit — so one diode handles the positive half-cycle and the other handles the negative half-cycle.

The peak inverse voltage is about 2Vm, because the non-conducting diode is exposed to both secondary half-voltages at once. That is double the PIV a bridge-rectifier diode must withstand.

The load only sees half of the total secondary voltage, so the peak is Vm minus one diode drop: Vout(peak) ≈ Vm − 0.7 V for a silicon diode.

Twice the supply frequency (2f). For a 50 Hz supply the output ripple is 100 Hz, which is easier to filter than the 50 Hz ripple of a half-wave rectifier.

The centre-tapped design loses only one diode drop (good for low voltages) but needs a costly centre-tapped transformer and diodes rated for 2Vm. The bridge rectifier needs four diodes (two drops) but uses an ordinary transformer and lower-PIV diodes. Modern supplies usually favour the bridge rectifier.

Its maximum rectification efficiency is about 81.2% — twice that of a half-wave rectifier (40.6%) — because both half-cycles deliver power to the load.